- Submitted By: samipk
- Date Submitted: 07/12/2010 8:25 AM
- Category: Business
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Assignment No.4 (Course STA301)

Spring 2010 (Total Marks 30)

Deadline

Your Assignment must be uploaded/ submitted before or on

23:59,1st July, 2010

Assignment.4 (Lessons 23-27)

Question 1: Marks: 3+7=10

a)

Find mean from the following probability distribution.

Solution:

|No of petals |P(X) |X.P(X) |

|X | | |

|3 |0.05 |0.15 |

|4 |0.10 |0.4 |

|5 |0.20 |1 |

|6 |0.30 |1.8 |

|7 |0.25 |1.75 |

|8 |0.075 |0.6 |

|9 |0.025 |0.225 |

|Total |1 |∑X.P(X) = 5.925 |

b) A random variable X has the following probability distribution:

|X |P(X) |

|-2 |0.1 |

|-1 |k |

|0 |0.2 |

|1 |2k |

|2 |0.3 |

|3 |3k |

Find

i) K

|X |P(X) |

|-2 |0.1 |

|-1 |K |

|0 |0.2 |

|1 |2k |

|2 |0.3 |

|3 |3k |

|Total |∑P(X) = 0.6+6k |

The sum of the probabilities is equal to 1

[pic]

Substituting values of k,

|X...