1. How many total bits/sec for the network would you expect to be sent for the frame size of 256 bytes?
1/0.005 = 200 frames per second
1 byte = (200) (256) (8) bits / second = 409,600 bps
10 stations x 409,600 bps = 4,096,000 bps = 4.096 Mbps = total traffic sent
When using a frame size of 256 bytes, the network is expected to have a speed of 4.096 Mbps.
2. How many total bits/sec for the network would you expect to be sent for the frame size of 512 bytes?
1/0.005 = 200 frames per second
1 byte = (200) (512) (8) bits / second = 819,200 bps
10 stations x 819,200 bps = 8,192,000 bps = 8.192 Mbps = total traffic sent
When using a frame size of 512 bytes, the network is expected to have a speed of 8.192 Mbps.
3. How many total bits/sec for the network would you expect to be sent for the frame size of 1,024 bytes?
1/0.005 = 200 frames per second
1 byte = (200) (1024) (8) bits / second = 1,638,400 bps
10 stations x 1,638,400 bps = 16,384,000 bps = 16.384 Mbps = total traffic sent
When using a frame size of 1024 bytes, the network is expected to have a speed of 16.384 Mbps.
4. Compare the simulation results for the PK256_10Mbps run with your calculations from Question 1 part (a). Are they about the same?
When comparing the simulation results to the calculation, the results are almost identical.
5. Compare the simulation results for the PK512_10Mbps run with your calculations from Question 1 part (a). Are they about the same?
When comparing the simulation results to the calculation, the results are almost identical.
6. Compare the simulation results for the PK1024_10Mbps run with your calculations from Question 1 part (a). Are they about the same?
When comparing the simulation results to the calculation, the results are almost identical.
7. For the PK256_10Mbps run, compare the total traffic sent to the total traffic received. Are they the same? Would you expect them to be about the same? Why or why not?...