Assignment 1
DETAIL ANALYSIS 1: System Design
Air conditioning system = 10KW , Sauna system = 30KW
* Intends to use heat generated from the condenser in air conditioning system to build a sauna system so the electricity of the sauna system can be save.
* Air conditioning operates on R134a, and coefficient of performance (COP) is 3.0
* Condenser :
Inlet Outlet
T = 90o C T = 60oC
P = 1.2 MPa P = 1.2 Mpa
CALCULATION:
* COP = QL / Win
* QL = (COP)Win
= (3.0) (10 KW) = 30KW
* QH = QL + Win
= (30KW) + 10KW = 40 KW
R 134 a
* QH = mref (hin – hout) hin at P = 1.2 Mpa, T is 90o C = 322.07 Kj/Kg
40Kj/s = mref (322.07 – 289.64)Kj/Kg hin at P = 1.2 Mpa, T is 60oC = 289.64 Kj/Kg
mref = 1.23kg/s
* It is proven that sauna system can use the heat generated by the condenser because it generated 40 KW but the sauna system need 30 KW to produce temperature 65oC.
DICUSSION:
Cost Savings:-
From using the heat generated from the condenser for sauna system, the residential can save;
* Power consumed for the sauna = 30 KW
* The total number of hours in a year, ASSUME residential use 2 hours per day,
* Annual hours → (365 days/yr) × (2 h/yr) = 730 h/yr
* Power consumption per year → (Ẇ total) × (operating hours)
→ (30KW) × (730 h/yr) = 21900 KW h/yr
* Power cost → (Power consumption) × (unit cost)
→ (21900 KW h/yr) × (RM0.25 KWh) = RM 5475.00 yr
* By using the heat generated by condenser, the residential can save RM 5475.00 per year and also save the electricity.
DETAIL ANALYSIS 2: Coal
* Electricity conservation 40%, transmission losses 10%, distribution losses 15%
* The electricity production cost is RM0.06 KWh, cost for residential is RM 0.25 KWh
* Each electricity production consumes 0.4 kg of coal and emits 1.0kg of CO2 and 15g of SO2
CALCULATION:
Transmission losses produce:
* (21900...