Bayley McDermott
Bishnu Dhakal
Chemistry for Non-Majors
5 February 2016
Title: Caloric Content of a Nut
Protocol:
The mass of the heat shield was determined and recorded.
The mass of the nut was determined.
A 10ml graduated cylinder was used to measure 10ml of water into an aluminum weighing boat.
The initial mass of water is 10g (1ml is about 1g)
The nut was placed in the wire holder on the rubber stopper.
The rubber stopper was placed inside the ceramic triangle and the wind shield was placed on top of the triangle.
The weighing boat was placed on top of the wind shield.
The nut was set on fire until it would not burn anymore and evaporated out some of the water.
Results:
Lab Room Temperature
23.5°C
Type of Nut
Peanut
Mass of Nut
1.299g
Initial ml of H2O
10ml
Mass of Aluminum Heat Shield
1.387g
Mass of H2O
10g
Mass of H2O after heating (10g-4.4g)
5.6g
Mass of H2O vaporized (10g-5.6g)
4.4g
Calories used to raise H2O to 100 degrees
100-23.5=76.5*10=765
765 Calories
Calories used to vaporize H2O
(10g-5.6g) * 540cal/g=2,376
2,376 Calories
Calories absorbed by the Al shield
1.387*.214*31.5=9.35
9.35 Calories
Total calories generated by the nut
765+2,376+9.35=3,150.4
3,150.4 Calories
Total calories per gram
3,150.4/1.299=2,425.3
2,425.3 Calories
Food Calories per gram generated by the Nut
2,425.3/1000=2.4
2.4 Kcal
Findings/Conclusion:
Most of the water from the weighing boat was evaporated by the heat produced from the nut. The calories that were produced to make water evaporate is not the same as the calories we consume. The difference between grams that were used to vaporize and that were evaporated was only 1.2. The calories generated by the nut was 3,150.4 calories which was divided by the mass of the nut to see how much per gram. Then that 2,425.3 calories were divided by 1000 to see how many Kilocalories there are in the nut. The kilocalories is the calories we consume. There were only 2.4 Kcal...