- Submitted By: soccerzingy
- Date Submitted: 10/11/2010 11:37 PM
- Category: American History
- Words: 703
- Page: 3
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Question: Explain why the value obtained for the density of the metal is likely to have a larger percentage error than that found for the liquid.

Answer: The volume of the water will always be equal to the volume of the flask but the metal’s volume is calculated by us so there is more room for human calculation error.

Purpose (Cynthia Ahmed): To find the density of an unknown solid and liquid by using the measuring by difference technique.

Procedure (Cynthia Ahmed): An analytical balance and pnycometer is used to find the mass and volume of unidentified solids and liquids. Then, this data is used to calculate the densities of the solids and liquids to aid in identifying them.

Data and Calculations (Nisha Kanyan): Unknown Liquid# I Unknown Solid # A

Density of unknown liquid

Data:

Mass of empty flask + stopper= 45.012g

Mass of stopper + flask+H2O = 101.75g

Mass of stopper + flask + liquid= 90.520g

Mass of Water= 56.738g

Volume of flask= 56.897cm3

Mass of Liquid= 45.508g

Density of liquid= 0.79965g/cm3

Significant figures= 5

Water= 24.5oC=0.9972g/cm3

Calculations:

Mass of empty flask + stopper= measured

Mass of stopper + flask+H2O = measured

Mass of stopper + flask + liquid= measured

Mass of Water= Mass of stopper + flask+H2O- Mass of stopper + flask

Volume of flask= D=m/v (use density and mass of water)

Mass of Liquid= D=m/v (use volume of flask)

Density of liquid= D=m/v (use mass and volume of liquid)

Density of unknown solid

Data:

of metal= 1.9710g/cm3

Significant Figures= 5

Calculations: Mass of flask + stopper= 45.013g

Mass of stopper + flask + metal + H2O= 135.40g

Mass of metal= 68.110g

Mass of water= 22.278g

Volume of metal= 34.556cm3

Density

Mass of flask + stopper= measured

Mass of stopper + flask + metal + liquid= measured

Mass of metal Mass of stopper + flask + metal + H2O - Mass of stopper +...