Question: Explain why the value obtained for the density of the metal is likely to have a larger percentage error than that found for the liquid.
Answer: The volume of the water will always be equal to the volume of the flask but the metal’s volume is calculated by us so there is more room for human calculation error.
Purpose (Cynthia Ahmed): To find the density of an unknown solid and liquid by using the measuring by difference technique.
Procedure (Cynthia Ahmed): An analytical balance and pnycometer is used to find the mass and volume of unidentified solids and liquids. Then, this data is used to calculate the densities of the solids and liquids to aid in identifying them.
Data and Calculations (Nisha Kanyan): Unknown Liquid# I Unknown Solid # A
Density of unknown liquid
Mass of empty flask + stopper= 45.012g
Mass of stopper + flask+H2O = 101.75g
Mass of stopper + flask + liquid= 90.520g
Mass of Water= 56.738g
Volume of flask= 56.897cm3
Mass of Liquid= 45.508g
Density of liquid= 0.79965g/cm3
Significant figures= 5
Mass of empty flask + stopper= measured
Mass of stopper + flask+H2O = measured
Mass of stopper + flask + liquid= measured
Mass of Water= Mass of stopper + flask+H2O- Mass of stopper + flask
Volume of flask= D=m/v (use density and mass of water)
Mass of Liquid= D=m/v (use volume of flask)
Density of liquid= D=m/v (use mass and volume of liquid)
Density of unknown solid
of metal= 1.9710g/cm3
Significant Figures= 5
Calculations: Mass of flask + stopper= 45.013g
Mass of stopper + flask + metal + H2O= 135.40g
Mass of metal= 68.110g
Mass of water= 22.278g
Volume of metal= 34.556cm3
Mass of flask + stopper= measured
Mass of stopper + flask + metal + liquid= measured
Mass of metal Mass of stopper + flask + metal + H2O - Mass of stopper +...