exam

exam

´╗┐EXAM #2
Problem -1
a. 0.0401
b. .1587
c. .1359
d. 1.04
e. -1.64
f. 0.0455
g. .9599
h. .9332
i. 1.00 and -1.00

Problem -2
a. .1587
b. .0228
c. .3812
d. .1818
e. 51.2667
f. 43.5922
g. -.0600 and .0600
h. .4756
i. 1
Problem -3.
a. .2266
b. .3085
c. .6827
d. 0455
e. 102.6980
f. 98.9866
g. 97.90 and 102.10
h. .6827
i. 30

Problem -4.
a. 675.00
b. The sampling distribution is normally distributed because there is a large sample size (>30) so it
it follows the Central Limit Theorem .
c. 40429.32
d. 43906.68
e. yes
f. no
Problem -5.
a. 43.04
b. 41.9260
c. 50
d. 5.9292
e. The sampling distribution is normally distributed because there is a large sample size (>30) so it
it follows the Central Limit Theorem .
f. 31.12
g. 54.96
h. yes
i. no
Problem -6.













Ho - u=1; (The mean amount of paint is 1 gallon); H1 - u=/=1 (The mean amount of paint is not 1 gallon)


















a. Decision Rule states to reject Ho if lZstatl > 2.5758










b. test statistic: Zstat = (xBar - u)/(sd/n) = (.995 - 1) / (.02/sqrt 50) = -1.7678








c. 2.5758












d. .0771












e. lZstatl282; (The mean driving distance is greater than 282 yards); H1 - u1.6766. There is sufficient evidence to suggest that the mean driving distance is not greater
than 282
h. p-value = .0001 2.0017 or p-value 2.0017.There is sufficient to conclude that there is a difference in the means of the average spent
on couples vacationing in Jamaica versus Bermuda

h. p-value = .0001

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