Exercise 8.1.1
Network ID: 110 – 01101110
Host ID: b, c, d
00001010.00001010.00000001
Exercise 8.1.2
Class
Range of first byte
Network ID
Host ID
Possible Networks
Possible Host per Network
A
0-127
A
b. c. d
2(7)
2(24)
B
128-191
A. B
c. d
2(14)
2(16)
C
192-223
a. b. c
D
2(21)
2(8)
Exercise 8.1.3
Yes the first octet of 192 which is class C
Exercise 8.1.4
190.8-8.4-10111110-1000.100
Exercise 8.1.5
What is the slash notation equivalent of subnet mask 255.255.255.0?
11111111.10000000.00000000.00000000(2)
Count the “ones” = 24/24
What is the slash (or CIDR) notation equivalent of subnet mask 255.128.0.0?
11111111.10000000.00000000.00000000(2)
Count the “ones” = 9/9
Exercise 8.1.6
Block Size
Starting IP Address
Ending IP Address
Subnet Mask
24-bit block
10.0.0.0
10.255.255.255
255.0.0.0
20-bit block
172.16.0.0
172.31.255.255
255.255.0.0
16-bit block
192.168.0.0
192.168.255.255
255.255.255.0
Lab 8.1 Review
1. It is a class C it starts with 192. I am able to identify it by both the first octet and the subnet mask. Yes, it is part of the private address block.
2. Using Subnet Mask addressing expands the capabilities while holding rules because of the wide variety of numbers that can be assigned. Not just IP address matters, now the Subnet Mask plays a part as well
Lab 8.2.1
Lab 8.2 Review
1. With assigning static IP addresses on a home or small office if gives you the capability of finding the computer that is having problems much easier.
2. Assigning a static IP addresses becomes a problem when you have a large amount of host or the network changes regularly. DHCP helps because it allows the network to adapt automatically to new networks.