# Specific heat

## Specific heat

April 25, 2016
Heat Found In Metals
Results:
Data Table 1: Mass Data
Material
Mass (g) Trial 1
Mass (g) Trial 2
Metal
73.80 g
12.27 g
Calorimeter
4.82 g
4.82 g
Calorimeter + Water
109.07 g
90.70 g
Water 3-2
104.25 g
85.88 g

Data Table 2: Temperature Data
Material
Temperature (*C) Trial 1
Temperature (*C) Trial 2
Boiling Water in Water Bath (metal)
98.4 *C
98.4 *C
Water in Calorimeter
22.4 *C
21.0 *C
Water in Calorimeter After Metal Was Added
24.7 *C
26.8 *C
Temperature Change for Water 3-2
2.3 *C
5.8 *C
Temperature Change for Metal 3-1
-73.7 *C
-71.06 *C

Data Table 3: Heat Data

Column1
Trial 1
Trial 2
Heat Gained by Water (J)
1002.26 J
1364.12 J
Specific Heat of Metal (J/g*C)
0.179
1.55
Identity of Metal
Tin
Aluminum
Actual Specific Heat of Metal
0.217
0.904
Percent Error
17.5%
71.5%

Calculations:
Tin:
Heat gained by water: Q=(104.25)(2.4)(4.18) = 1002.26 J
Specific heat of metal:
Percent error: 100 = 17.5%
Aluminum:
Heat gained by water: (85.88)(3.8)(4.18)= 1364.12 J
Specific heat of metal:
Percent error: 100 = 71.5%
Data Analysis:
There were many calculations performed in this lab. Q=SM could be used to find the heat gained by water. To find the heat gained by water, the students had to multiply the specific heat of water, the mass of water, and the temperature change of water together. To find the specific heat of the metal, the students had to divide the heat gained by water by the mass of metal times the temperature change of the metal. To find the percent error, the students had to subtract the specific heat of metal from the actual specific heat of the metal and then it had to be dived by the actual specific heat of the metal and then multiplied by 100. In this lab, these equations were used to help find the answers to the third data table.
There were few errors that occurred or could have occurred in the lab. One error was when the students put the hot metal in...