- Submitted By: galaxyapple6
- Date Submitted: 07/06/2016 5:56 AM
- Category: Book Reports
- Words: 304
- Page: 2

BC=2.64m, AC=2m, Angel C=65

By cosine rule,

AB=√2.642 + 22 - 2(2.5)(2) cos65

AB=2.6m

The measurement of AB is 2.5m but the answer can be acceptable because the rope was not fixed enough and the ground level is not flat.

By sine rule,

=

Angle B=44

The measurement of angle B is 45 but this answer can be acceptable because we used angle paper and the grass is so dense.

Angel A=180-(65+44)

=71

The measurement of angle A is 70 but this answer can be acceptable because we use angle protector and the grass is so dense.

The area by using sign rule,

A= x 2.64 x 2 x sine 65

A=2.4m2

Area, A= b h

A= x 2 x 2

A=2m2

We can accept the area of the triangle because of the calibration error when we measure the height of the triangle.

AC=3.85m, BC=2m,Angel C=40

AB=√3.852+22-2(3.85)(2) cos40

AB=2.6m

The measurement of AB is 2.5m but the answer can be acceptable because the rope was not fixed enough and the ground level is not flat.

By sine rule,

=

Angel A=29

The measurement of angle B is 30 but this answer can be acceptable because we used angle paper and the grass is so dense.

Angel B=180-(29+40)

B=111

The measurement of angle A is 110 but this answer can be acceptable because we use angle protector and the grass is so dense.

The area by using sign rule,

A= x 3.85 x 2 x sine 40

A=2.4m2

Area, A= b h

A= x 2 x 2

A=2m2

We can accept the area of the triangle because of the calibration error when we measure the height of the triangle.