- Submitted By: laughloud4smiles
- Date Submitted: 02/17/2009 7:44 PM
- Category: Miscellaneous
- Words: 730
- Page: 3
- Views: 407

For my scale model project, I worked with Laurie Breed on enlarging a Jell-O pudding box. We enlarged the Jell-O box by a scale factor of 10. The length of our original object was 8.5 centimeters, the width of the original was 3.5 centimeters, and the height of the original object was 7 centimeters. When we enlarged our object, the length of the model was 85 centimeters, the width was 35 centimeters, and the height of our model was 70 centimeters. To create our enlarged model of a Jell-O pudding box, Laurie and I used mainly poster board, along with paint. When you enlarge a common object, I think that the volume of the object will become equivalent to the scale factor multiplied by itself. In the case of the Jell-O box, this would mean that the volume would be 100 times as large as the volume of the original box. I think that when you enlarge a common object, the surface area of the object will be equivalent to the scale factor multiplied by two. This would mean that the surface area would be 20 times as large as the surface area of the original pudding box.

Surface area is the sum of all the areas of each side of an object. On a rectangular prism, it is the sum of the areas of the six sides of the prism. The length of the original Jell-O box was 8.5 centimeters, the width was 3.5 centimeters, and the height measured at 7 centimeters. With the scale factor of 10, this made the length of the model 85 centimeters, the width 35 centimeters, and the height 70 centimeters. To find the surface area of a rectangular prism, I use the equation 2(L×W + W×H + H×L) = surface area, with ‘L’ representing length, ‘W’ representing width, and ‘H’ representing height. When I plugged in the measurements from the Jell-O box, I came up with the equation 2(8.5×3.5 + 3.5×7 + 7×8.5) = surface area. This first simplifies to 2(29.75 + 24.5 + 59.5) = surface area, and then I simplified it to 2(113.75) = surface area. When I multiplied 113.75 by 2, I found that the surface area of the...

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