The goal of this experiment is to measure the density of the given two blocks (Aluminum, wood) by directly obtaining the values according to the theories learned on density and making those results as a reference for the experiment on the indirect method (Archimedes’ Principle)
The ideology of this experiment is to calculate the objects buoyancy force while it is submerged in water then obtain volume of water displaced. Thereafter from the objects weight (on air) calculate the density of the block.
When a body is fully or partially submerged in a fluid a buoyant force (F_b) acts on the object from the fluid. The magnitude of this force is equal to the weight (m_f g) of the volume (V^ ) of fluid displaced by the object and it is directed upwards.
Therefor when an object is completely submerged in water, (Where the density of water is ρ_w )
The buoyant force is
The mass of the object in air is
(ρ) is density of object
The volume of the object
Direct method (Aluminium & Wood)
Calculate the Length, width and height of the two blocks using the ruler.
Record the values and convert units if necessary (mm to m)
Calculate volume for the blocks
Weigh the blocks on top pan balance and convert units if necessary
Using the equation for the density calculate each blocks density.
Volume of Aluminium block = Height x Length x Width
= 20mm x 25mm x 20mm
= 10000 〖mm〗^3
= 1 x 〖10〗^(-5) m^3
Mass of Aluminium block = 29.7 x 〖10〗^(-3) kg
Density of Aluminium block = (29.7 x 〖10〗^(-3) kg)/(1 x 〖10〗^(-5) m^3 )
Volume of wooden block = Height x Length x Width
= 30mm x 50mm x 50mm...