- Submitted By: anizah0103
- Date Submitted: 12/03/2014 4:47 AM
- Category: Business
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FACULTY OF BUSINESS AND MANAGEMENT

SEMESTER: MAY 2014

BBMP 1103

MATHEMATICS FOR MANAGEMENT

MATRICULATION NO :

TELEPHONE NO. :

E-MAIL :

LEARNING CENTRE :

QUESTION 1

a) Find the straight line that passes through point (2,4) and is perpendicular to line 2x + 12y – 6 = 0

Answer

m = 6

x1 = 2

y1 = 4

m = (y-y1) / (x-x1)

6 = (y-4) / (x-2)

y-4 = 6(x-2)

y-4 = 6x-12

y = 6x-12+4

y = 6x-8

b) Given the function y = 3x² – 11x + 6 = 0

What is the value of x?

Answer

y = 3x² - 11x + 6 = 0

(3x -2)(x-3) = 0

3x-2=0 x-3 = 0

x = 2/3 or x =3

QUESTION 2

Given the following information

Particulars

Product X

Product Y

Units sold (quantity)

400

500

RM

RM

Sales price per unit

50

80

Electricity expenses

10

12

Telephone expenses

13

14

Salaries expenses

16

18

Fixed cost rental expenses

2000

1000

You are required to calculate the following for both products:

a) Total revenue

b) Total cost

c) Total profit

d) Breakeven point in RM and units

e) Units need to be sold of profit of RM1000 is targeted

Answer 2(a)

Total revenue = Price per unit x Units sold (quantity)

Product X

Total revenue = RM50 x 400

= RM20,000.00

Product Y

Total revenue = RM80 x 500

= RM40,000.00

Total revenue for both product is RM60,000

Answer 2 (b)

Total cost = Fixed cost + Variable cost

Total cost for product X

2,000 + (10 + 13 + 16)q q = 400 (quantity sold)

2,000 + (39)(400)

2,000 + 15,600

Total cost for Product X is RM17,600

Total cost for product Y

1,000 + (12 + 14 + 18)q q = 500 (quantity sold)

1,000 + (44)(500)

1,000 + 22,000

Total cost for Product Y is RM23,000

Answer 2(c)

Total profit = Total revenue – Total cost

Total profit for product X

20,000 – 17,600

= RM2,400.00

Total profit for product Y

40,000 – 23,000

= RM17,000...